What is the general solution for 1-tan^2(x)=sec^2(x) ?

The general solution for 1-tan^2(x)=sec^2(x) is x=pin

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1-tan^2(x)=sec^2(x)

1 - tan^{2} (x) = sec^{2} (x)

x = πn

Solution steps

1 - tan^{2} (x) = sec^{2} (x)

Subtract

sec^{2} (x)

from both sides

1 - tan^{2} (x) - sec^{2} (x) = 0

Rewrite using trig identities

- 2 tan^{2} (x) = 0

Divide both sides by

- 2

tan (x) = 0

General solutions for

tan (x) = 0

x = 0 + πn

Solve

x = 0 + πn : x = πn

x = πn

cos (2 θ - \frac{π}{2}) = - 1, 0 \leq θ < 2 π

sinh (x) = - \frac{3}{4}

tan (3 θ) = 1

7 - 7 sin (θ) = 7

- 12 cos^{2} (θ) - 8 = - 17

What is the general solution for 1-tan^2(x)=sec^2(x) ?
The general solution for 1-tan^2(x)=sec^2(x) is x=pin