What is the general solution for 2cos(1/2 x)-sqrt(2)=0 ?

The general solution for 2cos(1/2 x)-sqrt(2)=0 is x= pi/2+4pin,x=(7pi)/2+4pin

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2cos(1/2 x)-sqrt(2)=0

Solution

2 cos (\frac{1}{2} x) - 2 = 0

Solution

x = \frac{π}{2} + 4 πn, x = \frac{7 π}{2} + 4 πn

Degrees

x = 9 0^{\circ} + 72 0^{\circ} n, x = 63 0^{\circ} + 72 0^{\circ} n

Solution steps

2 cos (\frac{1}{2} x) - 2 = 0

Move

2

to the right side

2 cos (\frac{1}{2} x) - 2 = 0

Add

2

to both sides

2 cos (\frac{1}{2} x) - 2 + 2 = 0 + 2

Simplify

2 cos (\frac{1}{2} x) = 2

2 cos (\frac{1}{2} x) = 2

Divide both sides by

2

2 cos (\frac{1}{2} x) = 2

Divide both sides by

2

\frac{2 cos ( \frac{1}{2} x )}{2} = \frac{2}{2}

Simplify

cos (\frac{1}{2} x) = \frac{2}{2}

cos (\frac{1}{2} x) = \frac{2}{2}

General solutions for

cos (\frac{1}{2} x) = \frac{2}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{1}{2} x = \frac{π}{4} + 2 πn, \frac{1}{2} x = \frac{7 π}{4} + 2 πn

\frac{1}{2} x = \frac{π}{4} + 2 πn, \frac{1}{2} x = \frac{7 π}{4} + 2 πn

Solve

\frac{1}{2} x = \frac{π}{4} + 2 πn : x = \frac{π}{2} + 4 πn

\frac{1}{2} x = \frac{π}{4} + 2 πn

Multiply both sides by

2

\frac{1}{2} x = \frac{π}{4} + 2 πn

Multiply both sides by

2

2 \cdot \frac{1}{2} x = 2 \cdot \frac{π}{4} + 2 \cdot 2 πn

Simplify

2 \cdot \frac{1}{2} x = 2 \cdot \frac{π}{4} + 2 \cdot 2 πn

Simplify

2 \cdot \frac{1}{2} x : x

2 \cdot \frac{1}{2} x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2} x

Cancel the common factor:

2

= x \cdot 1

Multiply:

x \cdot 1 = x

= x

Simplify

2 \cdot \frac{π}{4} + 2 \cdot 2 πn : \frac{π}{2} + 4 πn

2 \cdot \frac{π}{4} + 2 \cdot 2 πn

2 \cdot \frac{π}{4} = \frac{π}{2}

2 \cdot \frac{π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{4}

Cancel the common factor:

2

= \frac{π}{2}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 4 πn

= \frac{π}{2} + 4 πn

x = \frac{π}{2} + 4 πn

x = \frac{π}{2} + 4 πn

x = \frac{π}{2} + 4 πn

Solve

\frac{1}{2} x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{2} + 4 πn

\frac{1}{2} x = \frac{7 π}{4} + 2 πn

Multiply both sides by

2

\frac{1}{2} x = \frac{7 π}{4} + 2 πn

Multiply both sides by

2

2 \cdot \frac{1}{2} x = 2 \cdot \frac{7 π}{4} + 2 \cdot 2 πn

Simplify

2 \cdot \frac{1}{2} x = 2 \cdot \frac{7 π}{4} + 2 \cdot 2 πn

Simplify

2 \cdot \frac{1}{2} x : x

2 \cdot \frac{1}{2} x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2} x

Cancel the common factor:

2

= x \cdot 1

Multiply:

x \cdot 1 = x

= x

Simplify

2 \cdot \frac{7 π}{4} + 2 \cdot 2 πn : \frac{7 π}{2} + 4 πn

2 \cdot \frac{7 π}{4} + 2 \cdot 2 πn

2 \cdot \frac{7 π}{4} = \frac{7 π}{2}

2 \cdot \frac{7 π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{7 π 2}{4}

Multiply the numbers:

7 \cdot 2 = 14

= \frac{14 π}{4}

Cancel the common factor:

2

= \frac{7 π}{2}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 4 πn

= \frac{7 π}{2} + 4 πn

x = \frac{7 π}{2} + 4 πn

x = \frac{7 π}{2} + 4 πn

x = \frac{7 π}{2} + 4 πn

x = \frac{π}{2} + 4 πn, x = \frac{7 π}{2} + 4 πn

Popular Examples

cos(pi/x)=0

cos (\frac{π}{x}) = 0

tan^2(θ)-4sec(θ)=-5

tan^{2} (θ) - 4 sec (θ) = - 5

tan(θ)= 5/6

tan (θ) = \frac{5}{6}

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sin (3 x) cos (2 x) + cos (3 x) sin (2 x) = 1

tan^2(θ)+4tan(θ)=3

tan^{2} (θ) + 4 tan (θ) = 3

Frequently Asked Questions (FAQ)

What is the general solution for 2cos(1/2 x)-sqrt(2)=0 ?
The general solution for 2cos(1/2 x)-sqrt(2)=0 is x= pi/2+4pin,x=(7pi)/2+4pin