What is the general solution for 4sin(c)+3=sin(c)+1 ?

The general solution for 4sin(c)+3=sin(c)+1 is c=-0.72972…+2pin,c=pi+0.72972…+2pin

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4sin(c)+3=sin(c)+1

4 sin (c) + 3 = sin (c) + 1

c = - 0.72972 \dots + 2 πn, c = π + 0.72972 \dots + 2 πn

Solution steps

4 sin (c) + 3 = sin (c) + 1

Solve by substitution

sin (c) = - \frac{2}{3}

sin (c) = - \frac{2}{3} : c = arcsin (- \frac{2}{3}) + 2 πn, c = π + arcsin (\frac{2}{3}) + 2 πn

Combine all the solutions

c = arcsin (- \frac{2}{3}) + 2 πn, c = π + arcsin (\frac{2}{3}) + 2 πn

Show solutions in decimal form

c = - 0.72972 \dots + 2 πn, c = π + 0.72972 \dots + 2 πn

(tan (x) + 1) (3 tan (x) - 1) = 0

tan^{2} (x) sin (x) - sin (x) = 0

2 cos^{2} (t) - 3 cos (t) + 1 = 0

sin (x + 3 0^{\circ}) = cos (x)

sin (\frac{π}{6} x) = 0

What is the general solution for 4sin(c)+3=sin(c)+1 ?
The general solution for 4sin(c)+3=sin(c)+1 is c=-0.72972…+2pin,c=pi+0.72972…+2pin