What is the general solution for -sin^2(x)+cos^2(x)=0 ?

The general solution for -sin^2(x)+cos^2(x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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-sin^2(x)+cos^2(x)=0

- sin^{2} (x) + cos^{2} (x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

- sin^{2} (x) + cos^{2} (x) = 0

Rewrite using trig identities

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

sin (θ) - cos (2 θ) = 0

sec (θ) = - \frac{5}{3}

3 sin (x) = 2 cos (x)

5 cot (x) + 2 csc^{2} (x) = 5

cos (2 x) = \frac{4}{5}

What is the general solution for -sin^2(x)+cos^2(x)=0 ?
The general solution for -sin^2(x)+cos^2(x)=0 is x= pi/4+pin,x=(3pi)/4+pin