What is the general solution for 4cos(3θ)=0 ?

The general solution for 4cos(3θ)=0 is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3

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4cos(3θ)=0

4 cos (3 θ) = 0

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

4 cos (3 θ) = 0

Divide both sides by

4

cos (3 θ) = 0

General solutions for

cos (3 θ) = 0

3 θ = \frac{π}{2} + 2 πn, 3 θ = \frac{3 π}{2} + 2 πn

Solve

3 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 θ = \frac{3 π}{2} + 2 πn : θ = \frac{π}{2} + \frac{2 πn}{3}

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

2 sin^{2} (x) + 5 cos (x) + 1 = 0

3 cos^{2} (x) - 2 cos (x) - 2 = 0

5 sin (5 x) = 0

sin (x) cos (x) - 2 sin (x) = sin (x)

- 7 sin^{2} (θ) + 2 sin (θ) + 7 = 0

What is the general solution for 4cos(3θ)=0 ?
The general solution for 4cos(3θ)=0 is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3