What is the general solution for 11(1-cos(θ))=sin^2(θ) ?

The general solution for 11(1-cos(θ))=sin^2(θ) is θ=2pin

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11(1-cos(θ))=sin^2(θ)

11 (1 - cos (θ)) = sin^{2} (θ)

θ = 2 πn

Solution steps

11 (1 - cos (θ)) = sin^{2} (θ)

Subtract

sin^{2} (θ)

from both sides

11 (1 - cos (θ)) - sin^{2} (θ) = 0

Rewrite using trig identities

10 + cos^{2} (θ) - 11 cos (θ) = 0

Solve by substitution

cos (θ) = 10, cos (θ) = 1

cos (θ) = 10 :

No Solution

cos (θ) = 1 : θ = 2 πn

Combine all the solutions

θ = 2 πn

cos^{2} (x) - \frac{1}{2} = 0, 0 \leq x \leq 2 π

x, tan (x) = tan (y)

4 cos (θ) + 3 = 0

2 cos^{2} (x) + 1 = 3 cos (x), 0 \leq x \leq 2 π

cos (x) = \frac{5}{9}

What is the general solution for 11(1-cos(θ))=sin^2(θ) ?
The general solution for 11(1-cos(θ))=sin^2(θ) is θ=2pin