What is the general solution for 1=sin^2(x) ?

The general solution for 1=sin^2(x) is x= pi/2+2pin,x=(3pi)/2+2pin

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1=sin^2(x)

1 = sin^{2} (x)

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

1 = sin^{2} (x)

Switch sides

sin^{2} (x) = 1

Solve by substitution

sin (x) = 1, sin (x) = - 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

- 2 sin^{2} (x) - cos (x) = - 1

tan^{2} (x) = 1 + sec (x)

8 sin^{2} (x) = 7

- 6 arcsin (3 x) = π

tan^{2} (p) = tan (p)

What is the general solution for 1=sin^2(x) ?
The general solution for 1=sin^2(x) is x= pi/2+2pin,x=(3pi)/2+2pin