What is the general solution for 2sin^2(θ)+3sin(θ)=0 ?

The general solution for 2sin^2(θ)+3sin(θ)=0 is θ=2pin,θ=pi+2pin

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2sin^2(θ)+3sin(θ)=0

2 sin^{2} (θ) + 3 sin (θ) = 0

θ = 2 πn, θ = π + 2 πn

Solution steps

2 sin^{2} (θ) + 3 sin (θ) = 0

Solve by substitution

sin (θ) = 0, sin (θ) = - \frac{3}{2}

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

sin (θ) = - \frac{3}{2} :

No Solution

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

sin (x + \frac{π}{6}) + sin (x - \frac{π}{6}) = - \frac{3}{2}

3 csc (\frac{2 x}{3}) - 2 = 0

cos (θ) = \frac{8}{10}

5 sin (a) + 3 = sin (a) + 2

csc (3 x) = 2

What is the general solution for 2sin^2(θ)+3sin(θ)=0 ?
The general solution for 2sin^2(θ)+3sin(θ)=0 is θ=2pin,θ=pi+2pin