What is the general solution for sin^2(θ)-sin(θ)=0 ?

The general solution for sin^2(θ)-sin(θ)=0 is θ= pi/2+2pin,θ=2pin,θ=pi+2pin

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sin^2(θ)-sin(θ)=0

sin^{2} (θ) - sin (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = 2 πn, θ = π + 2 πn

Solution steps

sin^{2} (θ) - sin (θ) = 0

Solve by substitution

sin (θ) = 1, sin (θ) = 0

sin (θ) = 1 : θ = \frac{π}{2} + 2 πn

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = 2 πn, θ = π + 2 πn

2 cos^{2} (x) - 1 = 0, 0 \leq x < 2 π

cos (x + \frac{π}{2}) = sin (x)

cos (x) tan (x) + cos (x) = 0

2 sin^{2} (2 θ) = 1 + sin (2 θ)

sin (2 x) - cos (x) = 0, 0 \leq x \leq 2 π

What is the general solution for sin^2(θ)-sin(θ)=0 ?
The general solution for sin^2(θ)-sin(θ)=0 is θ= pi/2+2pin,θ=2pin,θ=pi+2pin