What is the general solution for sec(x)-sqrt(2)=0 ?

The general solution for sec(x)-sqrt(2)=0 is x= pi/4+2pin,x=(7pi)/4+2pin

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sec(x)-sqrt(2)=0

sec (x) - 2 = 0

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Degrees

x = 4 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n

Solution steps

sec (x) - 2 = 0

Move

2

to the right side

sec (x) - 2 = 0

Add

2

to both sides

sec (x) - 2 + 2 = 0 + 2

Simplify

sec (x) = 2

sec (x) = 2

General solutions for

sec (x) = 2

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

2 sin^{4} (x) + sin^{2} (x) - 1 = 0

tan (\frac{x}{9}) + 3 = 0

cos (θ) = \frac{6}{9}

sec (b) = 2

2 sin^{2} (x) - 4 sin (x) = cos^{2} (x) - 2

What is the general solution for sec(x)-sqrt(2)=0 ?
The general solution for sec(x)-sqrt(2)=0 is x= pi/4+2pin,x=(7pi)/4+2pin