What is the general solution for 16sin^2(x)+24sin(x)+8=0 ?

The general solution for 16sin^2(x)+24sin(x)+8=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin,x=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16sin^2(x)+24sin(x)+8=0

16 sin^{2} (x) + 24 sin (x) + 8 = 0

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

16 sin^{2} (x) + 24 sin (x) + 8 = 0

Solve by substitution

sin (x) = - \frac{1}{2}, sin (x) = - 1

sin (x) = - \frac{1}{2} : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn, x = \frac{3 π}{2} + 2 πn

1 - 3 tan^{2} (x) = 0

6 tan^{2} (θ) - 10 tan (θ) + 1 = - 5 tan (θ)

2 sin (2 x) + 6 sin (x) - 2 cos (x) = 3

sin (2 x) = \frac{4}{5}

2 csc (x) + 17 = 15 + csc (x)

What is the general solution for 16sin^2(x)+24sin(x)+8=0 ?
The general solution for 16sin^2(x)+24sin(x)+8=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin,x=(3pi)/2+2pin