What is the general solution for -sin(B)-4=3sin(B)-5 ?

The general solution for -sin(B)-4=3sin(B)-5 is B=0.25268…+2pin,B=pi-0.25268…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-sin(B)-4=3sin(B)-5

- sin (B) - 4 = 3 sin (B) - 5

B = 0.25268 \dots + 2 πn, B = π - 0.25268 \dots + 2 πn

Solution steps

- sin (B) - 4 = 3 sin (B) - 5

Solve by substitution

sin (B) = \frac{1}{4}

sin (B) = \frac{1}{4} : B = arcsin (\frac{1}{4}) + 2 πn, B = π - arcsin (\frac{1}{4}) + 2 πn

Combine all the solutions

B = arcsin (\frac{1}{4}) + 2 πn, B = π - arcsin (\frac{1}{4}) + 2 πn

Show solutions in decimal form

B = 0.25268 \dots + 2 πn, B = π - 0.25268 \dots + 2 πn

cos^{2} (x) - 7 cos (x) - 1 = 0

sec^{2} (x) + tan (x) - 1 = 0

0 = sin (θ)

6 tan^{4} (x) - tan^{2} (x) - 2 = 0

t, x = sin (t)

What is the general solution for -sin(B)-4=3sin(B)-5 ?
The general solution for -sin(B)-4=3sin(B)-5 is B=0.25268…+2pin,B=pi-0.25268…+2pin