What is the general solution for 1-cos(θ)=1+cos(θ) ?

The general solution for 1-cos(θ)=1+cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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1-cos(θ)=1+cos(θ)

1 - cos (θ) = 1 + cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

1 - cos (θ) = 1 + cos (θ)

Solve by substitution

cos (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

cos (2 x) + cos (x) = 1

tan (x) sec (x) = - 2 tan (x)

1 + sin^{2} (x) = 2

sin (\frac{3 π}{2} + x) + sin (\frac{3 π}{2} + x) = - 2

cos (x) tan (x) = 0

What is the general solution for 1-cos(θ)=1+cos(θ) ?
The general solution for 1-cos(θ)=1+cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin