What is the general solution for solvefor θ,3cos(θ)=1+cos(θ) ?

The general solution for solvefor θ,3cos(θ)=1+cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin

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solvefor θ,3cos(θ)=1+cos(θ)

solve for

θ, 3 cos (θ) = 1 + cos (θ)

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

3 cos (θ) = 1 + cos (θ)

Solve by substitution

cos (θ) = \frac{1}{2}

cos (θ) = \frac{1}{2} : θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Combine all the solutions

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

tan (a) = \frac{5}{12}, sin (a) < 0, sin (a) + cos (a)

cot (2 x) = 3, 0 \leq x \leq 2 π

cot (θ) = \frac{5}{3}

cos (2 θ) = \frac{3}{5}

cos (\frac{x}{3}) = \frac{1}{2}

What is the general solution for solvefor θ,3cos(θ)=1+cos(θ) ?
The general solution for solvefor θ,3cos(θ)=1+cos(θ) is θ= pi/3+2pin,θ=(5pi)/3+2pin