What is the general solution for 1/2+cos(θ)=0 ?

The general solution for 1/2+cos(θ)=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/2+cos(θ)=0

\frac{1}{2} + cos (θ) = 0

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

\frac{1}{2} + cos (θ) = 0

Move

\frac{1}{2}

to the right side

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

(2 cos (x) - 1) (2 sin (x) + 3) = 0

2 sin (2 x) = 2 cos (x)

tan (\frac{1}{2} x) + 1 = 0

2 sin^{2} (θ) + 3 sin (θ) = - 1

tan (4 x) - 3 = 0

What is the general solution for 1/2+cos(θ)=0 ?
The general solution for 1/2+cos(θ)=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin