What is the general solution for 2cos(x)+3=0 ?

The general solution for 2cos(x)+3=0 is No Solution for x\in\mathbb{R}

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2cos(x)+3=0

2 cos (x) + 3 = 0

No Solution for x \in R

Solution steps

2 cos (x) + 3 = 0

Move

3

to the right side

2 cos (x) + 3 = 0

Subtract

3

from both sides

2 cos (x) + 3 - 3 = 0 - 3

Simplify

2 cos (x) = - 3

2 cos (x) = - 3

Divide both sides by

2

2 cos (x) = - 3

Divide both sides by

2

\frac{2 cos ( x )}{2} = \frac{- 3}{2}

Simplify

cos (x) = - \frac{3}{2}

cos (x) = - \frac{3}{2}

- 1 \leq cos (x) \leq 1

No Solution for x \in R

cos (θ) = - \frac{4}{9}

cos^{2} (x) + 2 cos (x) = sin^{2} (\frac{x}{2}) - 2

2 cos^{2} (x) - 4 cos (x) + 2 = 0

cos^{2} (x) - sin^{2} (x) = 1 - 2 sin (x)

cos (x) = - 0.34

What is the general solution for 2cos(x)+3=0 ?
The general solution for 2cos(x)+3=0 is No Solution for x\in\mathbb{R}