What is the general solution for 0=2+4sin(x) ?

The general solution for 0=2+4sin(x) is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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0=2+4sin(x)

0 = 2 + 4 sin (x)

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

0 = 2 + 4 sin (x)

Switch sides

2 + 4 sin (x) = 0

Move

2

to the right side

4 sin (x) = - 2

Divide both sides by

4

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (x) = \frac{1}{5}

cos (x) + cos (x) tan (x) = 0

4 sin^{3} (x) - sin (x) = 0

sin (θ) = 0.49

2 - sin^{2} (x) = 1 + cos (x)

What is the general solution for 0=2+4sin(x) ?
The general solution for 0=2+4sin(x) is x=(7pi)/6+2pin,x=(11pi)/6+2pin