What is the general solution for cos(4x)*4=0 ?

The general solution for cos(4x)*4=0 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2

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cos(4x)*4=0

cos (4 x) \cdot 4 = 0

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

cos (4 x) \cdot 4 = 0

Divide both sides by

4

cos (4 x) = 0

General solutions for

cos (4 x) = 0

4 x = \frac{π}{2} + 2 πn, 4 x = \frac{3 π}{2} + 2 πn

Solve

4 x = \frac{π}{2} + 2 πn : x = \frac{π}{8} + \frac{πn}{2}

Solve

4 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{8} + \frac{πn}{2}

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

cos^{2} (x) = \frac{3}{2}

sin (\frac{x}{2}) = \frac{3}{5}

16 cos^{2} (x) - 8 = 0

2 sin (4 θ) = 0

θ, 4 sin^{2} (\frac{θ}{2}) + 8 cos (\frac{θ}{2}) - 7 = 0

What is the general solution for cos(4x)*4=0 ?
The general solution for cos(4x)*4=0 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2