What is the general solution for 3sin(B)-2=5sin(B)-1 ?

The general solution for 3sin(B)-2=5sin(B)-1 is B=(7pi)/6+2pin,B=(11pi)/6+2pin

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3sin(B)-2=5sin(B)-1

3 sin (B) - 2 = 5 sin (B) - 1

B = \frac{7 π}{6} + 2 πn, B = \frac{11 π}{6} + 2 πn

Solution steps

3 sin (B) - 2 = 5 sin (B) - 1

Solve by substitution

sin (B) = - \frac{1}{2}

sin (B) = - \frac{1}{2} : B = \frac{7 π}{6} + 2 πn, B = \frac{11 π}{6} + 2 πn

Combine all the solutions

B = \frac{7 π}{6} + 2 πn, B = \frac{11 π}{6} + 2 πn

sin (x) = sin (- x)

3 cos (θ) + 2 = 0

- cot (x) - 3 cos (x) = - cot (x) cos (x) - 3 cos (x)

6 cos^{2} (x) + 3 cos (x) = 0

6 sin (A) + 4 = 2 sin (A) + 8

What is the general solution for 3sin(B)-2=5sin(B)-1 ?
The general solution for 3sin(B)-2=5sin(B)-1 is B=(7pi)/6+2pin,B=(11pi)/6+2pin