What is the general solution for arccos(x)=1 ?

The general solution for arccos(x)=1 is x=cos(1)

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arccos(x)=1

arccos (x) = 1

x = cos (1)

Solution steps

arccos (x) = 1

Apply trig inverse properties

arccos (x) = 1

arccos (x) = a \Rightarrow x = cos (a)

x = cos (1)

x = cos (1)

cos (x) = \frac{3}{4}

sin (x) = sin (\frac{x}{2})

sec (x) - 2 = - tan (x) - 3

- 9.81 + 5 (32.17) (\frac{12}{2}) sin (θ) = 0

2 sin^{3} (x) - sin^{2} (x) - 2 sin (x) + 1 = 0

What is the general solution for arccos(x)=1 ?
The general solution for arccos(x)=1 is x=cos(1)