What is the general solution for 9cos(x)=0 ?

The general solution for 9cos(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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9cos(x)=0

9 cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

9 cos (x) = 0

Divide both sides by

9

9 cos (x) = 0

Divide both sides by

9

\frac{9 cos ( x )}{9} = \frac{0}{9}

Simplify

cos (x) = 0

cos (x) = 0

General solutions for

cos (x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

18 arcsin (x) = 3 π

(2 cos (x) - 3) (2 sin (x) - 1) = 0

11 tan (θ) - 10 = 4 tan (θ) - 4

sec^{2} (x) - 8 sec (x) = 0

cot^{2} (x) = 1 + csc (x)

What is the general solution for 9cos(x)=0 ?
The general solution for 9cos(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin