What is the general solution for cot(x)+6sin(x)-2cos(x)=3 ?

The general solution for cot(x)+6sin(x)-2cos(x)=3 is x= pi/6+2pin,x=(5pi)/6+2pin,x=0.32175…+pin

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Popular >

cot(x)+6sin(x)-2cos(x)=3

Solution

cot (x) + 6 sin (x) - 2 cos (x) = 3

Solution

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = 0.32175 \dots + πn

Degrees

x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n, x = 18.43494 \dots^{\circ} + 18 0^{\circ} n

Solution steps

cot (x) + 6 sin (x) - 2 cos (x) = 3

Subtract

3

from both sides

cot (x) + 6 sin (x) - 2 cos (x) - 3 = 0

Express with sin, cos

- 3 + cot (x) - 2 cos (x) + 6 sin (x)

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

= - 3 + \frac{cos ( x )}{sin ( x )} - 2 cos (x) + 6 sin (x)

Simplify

- 3 + \frac{cos ( x )}{sin ( x )} - 2 cos (x) + 6 sin (x) : \frac{- 3 sin ( x ) + cos ( x ) - 2 cos ( x ) sin ( x ) + 6 sin ^{2} ( x )}{sin ( x )}

- 3 + \frac{cos ( x )}{sin ( x )} - 2 cos (x) + 6 sin (x)

Convert element to fraction:

3 = \frac{3 sin ( x )}{sin ( x )}, 2 cos (x) = \frac{2 cos ( x ) sin ( x )}{sin ( x )}, 6 sin (x) = \frac{6 sin ( x ) sin ( x )}{sin ( x )}

= - \frac{3 sin ( x )}{sin ( x )} + \frac{cos ( x )}{sin ( x )} - \frac{2 cos ( x ) sin ( x )}{sin ( x )} + \frac{6 sin ( x ) sin ( x )}{sin ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 sin ( x ) + cos ( x ) - 2 cos ( x ) sin ( x ) + 6 sin ( x ) sin ( x )}{sin ( x )}

- 3 sin (x) + cos (x) - 2 cos (x) sin (x) + 6 sin (x) sin (x) = - 3 sin (x) + cos (x) - 2 cos (x) sin (x) + 6 sin^{2} (x)

- 3 sin (x) + cos (x) - 2 cos (x) sin (x) + 6 sin (x) sin (x)

6 sin (x) sin (x) = 6 sin^{2} (x)

6 sin (x) sin (x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

sin (x) sin (x) = sin^{1 + 1} (x)

= 6 sin^{1 + 1} (x)

Add the numbers:

1 + 1 = 2

= 6 sin^{2} (x)

= - 3 sin (x) + cos (x) - 2 cos (x) sin (x) + 6 sin^{2} (x)

= \frac{- 3 sin ( x ) + cos ( x ) - 2 cos ( x ) sin ( x ) + 6 sin ^{2} ( x )}{sin ( x )}

= \frac{- 3 sin ( x ) + cos ( x ) - 2 cos ( x ) sin ( x ) + 6 sin ^{2} ( x )}{sin ( x )}

\frac{cos ( x ) - 3 sin ( x ) + 6 sin ^{2} ( x ) - 2 cos ( x ) sin ( x )}{sin ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos (x) - 3 sin (x) + 6 sin^{2} (x) - 2 cos (x) sin (x) = 0

Factor

cos (x) - 3 sin (x) + 6 sin^{2} (x) - 2 cos (x) sin (x) : (1 - 2 sin (x)) (cos (x) - 3 sin (x))

cos (x) - 3 sin (x) + 6 sin^{2} (x) - 2 cos (x) sin (x)

Factor out common term

cos (x)

= cos (x) (1 - 2 sin (x)) - 3 sin (x) + 6 sin^{2} (x)

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

sin^{2} (x) = sin (x) sin (x)

= cos (x) (1 - 2 sin (x)) - 3 sin (x) + 6 sin (x) sin (x)

Rewrite as

= cos (x) (1 - 2 sin (x)) - 1 \cdot 3 sin (x) + 2 \cdot 3 sin (x) sin (x)

Factor out common term

3 sin (x)

= cos (x) (1 - 2 sin (x)) + 3 sin (x) (- 1 + 2 sin (x))

Rewrite as

= (1 - 2 sin (x)) cos (x) - 3 (1 - 2 sin (x)) sin (x)

Factor out common term

(1 - 2 sin (x))

= (1 - 2 sin (x)) (cos (x) - 3 sin (x))

(1 - 2 sin (x)) (cos (x) - 3 sin (x)) = 0

Solving each part separately

1 - 2 sin (x) = 0 or cos (x) - 3 sin (x) = 0

1 - 2 sin (x) = 0 : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

1 - 2 sin (x) = 0

Move

1

to the right side

1 - 2 sin (x) = 0

Subtract

1

from both sides

1 - 2 sin (x) - 1 = 0 - 1

Simplify

- 2 sin (x) = - 1

- 2 sin (x) = - 1

Divide both sides by

- 2

- 2 sin (x) = - 1

Divide both sides by

- 2

\frac{- 2 sin ( x )}{- 2} = \frac{- 1}{- 2}

Simplify

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

cos (x) - 3 sin (x) = 0 : x = arctan (\frac{1}{3}) + πn

cos (x) - 3 sin (x) = 0

Rewrite using trig identities

cos (x) - 3 sin (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{cos ( x ) - 3 sin ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

1 - \frac{3 sin ( x )}{cos ( x )} = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

1 - 3 tan (x) = 0

1 - 3 tan (x) = 0

Move

1

to the right side

1 - 3 tan (x) = 0

Subtract

1

from both sides

1 - 3 tan (x) - 1 = 0 - 1

Simplify

- 3 tan (x) = - 1

- 3 tan (x) = - 1

Divide both sides by

- 3

- 3 tan (x) = - 1

Divide both sides by

- 3

\frac{- 3 tan ( x )}{- 3} = \frac{- 1}{- 3}

Simplify

tan (x) = \frac{1}{3}

tan (x) = \frac{1}{3}

Apply trig inverse properties

tan (x) = \frac{1}{3}

General solutions for

tan (x) = \frac{1}{3}

tan (x) = a \Rightarrow x = arctan (a) + πn

x = arctan (\frac{1}{3}) + πn

x = arctan (\frac{1}{3}) + πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = arctan (\frac{1}{3}) + πn

Show solutions in decimal form

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = 0.32175 \dots + πn

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Frequently Asked Questions (FAQ)

What is the general solution for cot(x)+6sin(x)-2cos(x)=3 ?
The general solution for cot(x)+6sin(x)-2cos(x)=3 is x= pi/6+2pin,x=(5pi)/6+2pin,x=0.32175…+pin