What is the general solution for solvefor t,x=cos(2t) ?

The general solution for solvefor t,x=cos(2t) is t=(arccos(x))/2+pin,t=-(arccos(x))/2+pin

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solvefor t,x=cos(2t)

solve for

t, x = cos (2 t)

t = \frac{arccos ( x )}{2} + πn, t = - \frac{arccos ( x )}{2} + πn

Solution steps

x = cos (2 t)

Switch sides

cos (2 t) = x

Apply trig inverse properties

2 t = arccos (x) + 2 πn, 2 t = - arccos (x) + 2 πn

Solve

2 t = arccos (x) + 2 πn : t = \frac{arccos ( x )}{2} + πn

Solve

2 t = - arccos (x) + 2 πn : t = - \frac{arccos ( x )}{2} + πn

t = \frac{arccos ( x )}{2} + πn, t = - \frac{arccos ( x )}{2} + πn

- 9 sin^{2} (θ) - 3 cos (θ) + 2 = - 5

csc (x) = - 1 + cot (x)

2 sin (3 x) = 3

4 sin (3 θ) = 7 cos (3 θ), 0^{\circ} \leq 3 θ < 72 0^{\circ}

cot (θ) = 4

What is the general solution for solvefor t,x=cos(2t) ?
The general solution for solvefor t,x=cos(2t) is t=(arccos(x))/2+pin,t=-(arccos(x))/2+pin