What is the general solution for 2sin(1/2 x)+sqrt(3)=0 ?

The general solution for 2sin(1/2 x)+sqrt(3)=0 is x=(8pi)/3+4pin,x=(10pi)/3+4pin

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2sin(1/2 x)+sqrt(3)=0

Solution

2 sin (\frac{1}{2} x) + 3 = 0

Solution

x = \frac{8 π}{3} + 4 πn, x = \frac{10 π}{3} + 4 πn

Degrees

x = 48 0^{\circ} + 72 0^{\circ} n, x = 60 0^{\circ} + 72 0^{\circ} n

Solution steps

2 sin (\frac{1}{2} x) + 3 = 0

Move

3

to the right side

2 sin (\frac{1}{2} x) + 3 = 0

Subtract

3

from both sides

2 sin (\frac{1}{2} x) + 3 - 3 = 0 - 3

Simplify

2 sin (\frac{1}{2} x) = - 3

2 sin (\frac{1}{2} x) = - 3

Divide both sides by

2

2 sin (\frac{1}{2} x) = - 3

Divide both sides by

2

\frac{2 sin ( \frac{1}{2} x )}{2} = \frac{- 3}{2}

Simplify

sin (\frac{1}{2} x) = - \frac{3}{2}

sin (\frac{1}{2} x) = - \frac{3}{2}

General solutions for

sin (\frac{1}{2} x) = - \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

\frac{1}{2} x = \frac{4 π}{3} + 2 πn, \frac{1}{2} x = \frac{5 π}{3} + 2 πn

\frac{1}{2} x = \frac{4 π}{3} + 2 πn, \frac{1}{2} x = \frac{5 π}{3} + 2 πn

Solve

\frac{1}{2} x = \frac{4 π}{3} + 2 πn : x = \frac{8 π}{3} + 4 πn

\frac{1}{2} x = \frac{4 π}{3} + 2 πn

Multiply both sides by

2

\frac{1}{2} x = \frac{4 π}{3} + 2 πn

Multiply both sides by

2

2 \cdot \frac{1}{2} x = 2 \cdot \frac{4 π}{3} + 2 \cdot 2 πn

Simplify

2 \cdot \frac{1}{2} x = 2 \cdot \frac{4 π}{3} + 2 \cdot 2 πn

Simplify

2 \cdot \frac{1}{2} x : x

2 \cdot \frac{1}{2} x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2} x

Cancel the common factor:

2

= x \cdot 1

Multiply:

x \cdot 1 = x

= x

Simplify

2 \cdot \frac{4 π}{3} + 2 \cdot 2 πn : \frac{8 π}{3} + 4 πn

2 \cdot \frac{4 π}{3} + 2 \cdot 2 πn

2 \cdot \frac{4 π}{3} = \frac{8 π}{3}

2 \cdot \frac{4 π}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{4 π 2}{3}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{8 π}{3}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 4 πn

= \frac{8 π}{3} + 4 πn

x = \frac{8 π}{3} + 4 πn

x = \frac{8 π}{3} + 4 πn

x = \frac{8 π}{3} + 4 πn

Solve

\frac{1}{2} x = \frac{5 π}{3} + 2 πn : x = \frac{10 π}{3} + 4 πn

\frac{1}{2} x = \frac{5 π}{3} + 2 πn

Multiply both sides by

2

\frac{1}{2} x = \frac{5 π}{3} + 2 πn

Multiply both sides by

2

2 \cdot \frac{1}{2} x = 2 \cdot \frac{5 π}{3} + 2 \cdot 2 πn

Simplify

2 \cdot \frac{1}{2} x = 2 \cdot \frac{5 π}{3} + 2 \cdot 2 πn

Simplify

2 \cdot \frac{1}{2} x : x

2 \cdot \frac{1}{2} x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2} x

Cancel the common factor:

2

= x \cdot 1

Multiply:

x \cdot 1 = x

= x

Simplify

2 \cdot \frac{5 π}{3} + 2 \cdot 2 πn : \frac{10 π}{3} + 4 πn

2 \cdot \frac{5 π}{3} + 2 \cdot 2 πn

2 \cdot \frac{5 π}{3} = \frac{10 π}{3}

2 \cdot \frac{5 π}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 π 2}{3}

Multiply the numbers:

5 \cdot 2 = 10

= \frac{10 π}{3}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiply the numbers:

2 \cdot 2 = 4

= 4 πn

= \frac{10 π}{3} + 4 πn

x = \frac{10 π}{3} + 4 πn

x = \frac{10 π}{3} + 4 πn

x = \frac{10 π}{3} + 4 πn

x = \frac{8 π}{3} + 4 πn, x = \frac{10 π}{3} + 4 πn

Popular Examples

0=-1/7 cos(7t)

0 = - \frac{1}{7} cos (7 t)

cos(α)= 5/13

cos (α) = \frac{5}{13}

tan(x)=sqrt(3),0<= x<= 2pi

tan (x) = 3, 0 \leq x \leq 2 π

3sec(θ)+7=0

3 sec (θ) + 7 = 0

(tan(x)+1)(sec(x)-1)=0

(tan (x) + 1) (sec (x) - 1) = 0

Frequently Asked Questions (FAQ)

What is the general solution for 2sin(1/2 x)+sqrt(3)=0 ?
The general solution for 2sin(1/2 x)+sqrt(3)=0 is x=(8pi)/3+4pin,x=(10pi)/3+4pin