What is the general solution for 0=sqrt(1-cos(2x)) ?

The general solution for 0=sqrt(1-cos(2x)) is x=pin

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0=sqrt(1-cos(2x))

0 = 1 - cos (2 x)

x = πn

Solution steps

0 = 1 - cos (2 x)

Switch sides

1 - cos (2 x) = 0

Square both sides:

1 - cos (2 x) = 0

1 - cos (2 x) = 0

Solve

1 - cos (2 x) = 0 : cos (2 x) = 1

cos (2 x) = 1

Verify Solutions:

cos (2 x) = 1

True

The solution is

cos (2 x) = 1

General solutions for

cos (2 x) = 1

2 x = 0 + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

x = πn

sec^{2} (x) + 2 = 3 sec (x)

cos (x) - 1 = - cos (x)

2 cos^{2} (x) = 3

9 tan (2 x) - 9 cot (x) = 0

sin (2 x) = 2 sin^{2} (x)

What is the general solution for 0=sqrt(1-cos(2x)) ?
The general solution for 0=sqrt(1-cos(2x)) is x=pin