What is the general solution for 1-2sin^2(x)=0 ?

The general solution for 1-2sin^2(x)=0 is x= pi/4+2pin,x=(3pi)/4+2pin,x=(5pi)/4+2pin,x=(7pi)/4+2pin

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1-2sin^2(x)=0

1 - 2 sin^{2} (x) = 0

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

1 - 2 sin^{2} (x) = 0

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2} : x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

sin (x) = - \frac{1}{2} : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Combine all the solutions

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

8 sin^{2} (θ) = 6

72 sin^{2} (x) = 72 - 36 cos (x)

3 cos^{2} (x) - 4 cos (x) + 1 = 0

cos (x) = 0.1

3 tan (x) = 2.4568

What is the general solution for 1-2sin^2(x)=0 ?
The general solution for 1-2sin^2(x)=0 is x= pi/4+2pin,x=(3pi)/4+2pin,x=(5pi)/4+2pin,x=(7pi)/4+2pin