What is the general solution for 1-2sin(θ)=0 ?

The general solution for 1-2sin(θ)=0 is θ= pi/6+2pin,θ=(5pi)/6+2pin

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1-2sin(θ)=0

1 - 2 sin (θ) = 0

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Solution steps

1 - 2 sin (θ) = 0

Move

1

to the right side

- 2 sin (θ) = - 1

Divide both sides by

- 2

sin (θ) = \frac{1}{2}

General solutions for

sin (θ) = \frac{1}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

cos (2 θ) + 3 cos (θ) = 4

0 = 2 cos (x) - 3 sin (x)

- cos (x) - sin (x) = 0

sin (x) = - \frac{1}{6}

sin (θ) = \frac{8}{14}

What is the general solution for 1-2sin(θ)=0 ?
The general solution for 1-2sin(θ)=0 is θ= pi/6+2pin,θ=(5pi)/6+2pin