What is the general solution for -4sin(2θ)=5cos(2θ),0<= 2θ<720 ?

The general solution for -4sin(2θ)=5cos(2θ),0<= 2θ<720 is No Solution for θ\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-4sin(2θ)=5cos(2θ),0<= 2θ<720

- 4 sin (2 θ) = 5 cos (2 θ), 0^{\circ} \leq 2 θ < 72 0^{\circ}

No Solution for θ \in R

Solution steps

- 4 sin (2 θ) = 5 cos (2 θ), 0^{\circ} \leq 2 θ < 72 0^{\circ}

Rewrite using trig identities

- 4 tan (2 θ) = 5

Divide both sides by

- 4

tan (2 θ) = - \frac{5}{4}

Apply trig inverse properties

2 θ = arctan (- \frac{5}{4}) + 18 0^{\circ} n

Solve

2 θ = arctan (- \frac{5}{4}) + 18 0^{\circ} n : θ = - \frac{arctan ( \frac{5}{4} )}{2} + \frac{18 0 ^{\circ} n}{2}

θ = - \frac{arctan ( \frac{5}{4} )}{2} + \frac{18 0 ^{\circ} n}{2}

Solutions for the range

0 \leq 2 θ < 72 0^{\circ}

No Solution for θ \in R

2 cos (2 x) + cos (x) - 1 = 0

0.79 = sin (x)

1 + cot (x) = csc (x)

4 cos^{2} (x) - 42 cos (x) + 2 = 0

sin (\frac{2 π}{3} - x) + sin (\frac{2 π}{3} + x) = 0

What is the general solution for -4sin(2θ)=5cos(2θ),0<= 2θ<720 ?
The general solution for -4sin(2θ)=5cos(2θ),0<= 2θ<720 is No Solution for θ\in\mathbb{R}