What is the general solution for 1=cos(((pi(t-22)))/(183)) ?

The general solution for 1=cos(((pi(t-22)))/(183)) is t=366n+22

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1=cos(((pi(t-22)))/(183))

1 = cos (\frac{( π ( t - 22 ) )}{183})

t = 366 n + 22

Solution steps

1 = cos (\frac{( π ( t - 22 ) )}{183})

Switch sides

cos (\frac{π ( t - 22 )}{183}) = 1

General solutions for

cos (\frac{π ( t - 22 )}{183}) = 1

\frac{π ( t - 22 )}{183} = 0 + 2 πn

Solve

\frac{π ( t - 22 )}{183} = 0 + 2 πn : t = 366 n + 22

t = 366 n + 22

cot (x) = - csc^{2} (x)

3 cos^{2} (θ) + 4 cos (θ) - 4 = 0

sin (x) = - cos^{2} (x) - 1

2 sin (x) cos (x) = 3 sin (x)

sin^{2} (x) = sin (2 x)

What is the general solution for 1=cos(((pi(t-22)))/(183)) ?
The general solution for 1=cos(((pi(t-22)))/(183)) is t=366n+22