What is the general solution for sin(x)+sqrt(3)=-sin(x) ?

The general solution for sin(x)+sqrt(3)=-sin(x) is x=(4pi)/3+2pin,x=(5pi)/3+2pin

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sin(x)+sqrt(3)=-sin(x)

sin (x) + 3 = - sin (x)

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

sin (x) + 3 = - sin (x)

Solve by substitution

sin (x) = - \frac{3}{2}

sin (x) = - \frac{3}{2} : x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Combine all the solutions

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

2 = cos (x)

12 sin^{2} (θ) - 6 sin (θ) = 5

cos^{3} (x) - sin^{2} (x) = 0

cos (c) = 0.87

8 sin^{2} (x) - 2 sin (x) - 1 = 0

What is the general solution for sin(x)+sqrt(3)=-sin(x) ?
The general solution for sin(x)+sqrt(3)=-sin(x) is x=(4pi)/3+2pin,x=(5pi)/3+2pin