What is the general solution for solvefor x,cos(x)=sin(y) ?

The general solution for solvefor x,cos(x)=sin(y) is x=arccos(sin(y))+2pin,x=-arccos(sin(y))+2pin

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solvefor x,cos(x)=sin(y)

solve for

x, cos (x) = sin (y)

x = arccos (sin (y)) + 2 πn, x = - arccos (sin (y)) + 2 πn

Solution steps

cos (x) = sin (y)

Apply trig inverse properties

cos (x) = sin (y)

General solutions for

cos (x) = sin (y)

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (sin (y)) + 2 πn, x = - arccos (sin (y)) + 2 πn

x = arccos (sin (y)) + 2 πn, x = - arccos (sin (y)) + 2 πn

tan (θ) = \frac{5}{8}

3 cos^{2} (x) = 9 sin (x) + 9

cos^{2} (x) - 2 cos (x) = 3

cos^{2} (x) = sin (x) + sin^{2} (x)

2 sin^{2} (x) = 1, + [0, + 2 π]

What is the general solution for solvefor x,cos(x)=sin(y) ?
The general solution for solvefor x,cos(x)=sin(y) is x=arccos(sin(y))+2pin,x=-arccos(sin(y))+2pin