What is the general solution for 2sin(x)+5=6 ?

The general solution for 2sin(x)+5=6 is x= pi/6+2pin,x=(5pi)/6+2pin

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2sin(x)+5=6

2 sin (x) + 5 = 6

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Degrees

x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n

Solution steps

2 sin (x) + 5 = 6

Move

5

to the right side

2 sin (x) + 5 = 6

Subtract

5

from both sides

2 sin (x) + 5 - 5 = 6 - 5

Simplify

2 sin (x) = 1

2 sin (x) = 1

Divide both sides by

2

2 sin (x) = 1

Divide both sides by

2

\frac{2 sin ( x )}{2} = \frac{1}{2}

Simplify

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (2 θ) - cos (2 θ) = 1

cos (θ) = \frac{1}{3}

tan (x) + \frac{1}{tan ( x )} = 2

4 csc (θ) - 5 = 3

csc (5 x) = - 1, 0 \leq x \leq 2 π

What is the general solution for 2sin(x)+5=6 ?
The general solution for 2sin(x)+5=6 is x= pi/6+2pin,x=(5pi)/6+2pin