What is the general solution for 1+cos(θ)=1-cos(θ) ?

The general solution for 1+cos(θ)=1-cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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1+cos(θ)=1-cos(θ)

1 + cos (θ) = 1 - cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

1 + cos (θ) = 1 - cos (θ)

Solve by substitution

cos (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

4 cos (x) - 22 = 0

sin (x) cos (3 x) + cos (x) sin (3 x) = 0

4 sin^{2} (x) + 4 = 5

2 csc (θ) + 3 = 0

2 cos (x) - 2 sin (2 x) = 0

What is the general solution for 1+cos(θ)=1-cos(θ) ?
The general solution for 1+cos(θ)=1-cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin