What is the general solution for sin(θ)= 3/5 ,cos(θ) ?

The general solution for sin(θ)= 3/5 ,cos(θ) is No Solution for θ\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)= 3/5 ,cos(θ)

sin (θ) = \frac{3}{5}, cos (θ)

No Solution for θ \in R

Solution steps

sin (θ) = \frac{3}{5}, cos (θ)

Apply trig inverse properties

sin (θ) = \frac{3}{5}

General solutions for

sin (θ) = \frac{3}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{3}{5}) + 2 πn, θ = π - arcsin (\frac{3}{5}) + 2 πn

θ = arcsin (\frac{3}{5}) + 2 πn, θ = π - arcsin (\frac{3}{5}) + 2 πn

Solutions for the range

cos (θ)

No Solution for θ \in R

cos (2 θ) + 2 cos^{2} (θ) = 0

csc^{2} (t) = 3

3 sin^{2} (θ) + 3 sin (θ) + 3 = 7 sin (θ) + 7

3 cos (x) = cos (x) - 1

2 sin^{2} (x) - 3 cos (x) - 3 = 0

What is the general solution for sin(θ)= 3/5 ,cos(θ) ?
The general solution for sin(θ)= 3/5 ,cos(θ) is No Solution for θ\in\mathbb{R}