What is the general solution for 2cot^2(x)-4=2 ?

The general solution for 2cot^2(x)-4=2 is x= pi/6+pin,x=(5pi)/6+pin

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2cot^2(x)-4=2

2 cot^{2} (x) - 4 = 2

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Solution steps

2 cot^{2} (x) - 4 = 2

Solve by substitution

cot (x) = 3, cot (x) = - 3

cot (x) = 3 : x = \frac{π}{6} + πn

cot (x) = - 3 : x = \frac{5 π}{6} + πn

Combine all the solutions

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

4 sin^{2} (θ) - 3 = 0, 0 \leq θ \leq 2 π

4 sin (B) + 8 = 0

4 cos (x) - 5 = - 7

0 = 1 + 2 sin (\frac{x ^{2}}{2})

cos (2 x) - 5 cos (x) + 3 = 0

What is the general solution for 2cot^2(x)-4=2 ?
The general solution for 2cot^2(x)-4=2 is x= pi/6+pin,x=(5pi)/6+pin