What is the general solution for 18sin^2(x)=9 ?

The general solution for 18sin^2(x)=9 is x= pi/4+2pin,x=(3pi)/4+2pin,x=(5pi)/4+2pin,x=(7pi)/4+2pin

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18sin^2(x)=9

18 sin^{2} (x) = 9

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

18 sin^{2} (x) = 9

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2} : x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

sin (x) = - \frac{1}{2} : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Combine all the solutions

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x, sin (x) = cos (y)

2 - 2 sin^{2} (\frac{x}{2}) = 2 cos^{2} (x)

2 cos (x) + 2 sin (x) = 6

6 tan (θ) + 1 = 0

cot (5 x) = - 1

What is the general solution for 18sin^2(x)=9 ?
The general solution for 18sin^2(x)=9 is x= pi/4+2pin,x=(3pi)/4+2pin,x=(5pi)/4+2pin,x=(7pi)/4+2pin