What is the general solution for 2cot(θ)+csc^2(θ)=0 ?

The general solution for 2cot(θ)+csc^2(θ)=0 is θ=(3pi)/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cot(θ)+csc^2(θ)=0

2 cot (θ) + csc^{2} (θ) = 0

θ = \frac{3 π}{4} + πn

Solution steps

2 cot (θ) + csc^{2} (θ) = 0

Rewrite using trig identities

1 + cot^{2} (θ) + 2 cot (θ) = 0

Solve by substitution

cot (θ) = - 1

cot (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{3 π}{4} + πn

csc (x) cot (x) = \frac{2}{3}

2 + 2 cos (x) = 0

4 tan^{2} (x) - 8 tan (x) + 3 = 0

sin (t) - sin (2 t) = 0

sin (\frac{3 x}{2}) = 0

What is the general solution for 2cot(θ)+csc^2(θ)=0 ?
The general solution for 2cot(θ)+csc^2(θ)=0 is θ=(3pi)/4+pin