What is the general solution for sin(x)-2sin^2(x)=0 ?

The general solution for sin(x)-2sin^2(x)=0 is x=2pin,x=pi+2pin,x= pi/6+2pin,x=(5pi)/6+2pin

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sin(x)-2sin^2(x)=0

sin (x) - 2 sin^{2} (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

sin (x) - 2 sin^{2} (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = \frac{1}{2}

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (2 θ) + sin (θ) = 0, 0 \leq θ < 2 π

7 sin (x) = cos (x) - 4

5 sin^{2} (θ) - 11 sin (θ) + 2 = 0

tan^{2} (θ) + 3 sec (θ) = - 3

cos^{2} (x) - sin^{2} (x) = 1 - sin^{2} (x)

What is the general solution for sin(x)-2sin^2(x)=0 ?
The general solution for sin(x)-2sin^2(x)=0 is x=2pin,x=pi+2pin,x= pi/6+2pin,x=(5pi)/6+2pin