What is the general solution for (cot(x)+1)(sin(x)+1)=0 ?

The general solution for (cot(x)+1)(sin(x)+1)=0 is x=(3pi)/4+pin,x=(3pi)/2+2pin

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(cot(x)+1)(sin(x)+1)=0

(cot (x) + 1) (sin (x) + 1) = 0

x = \frac{3 π}{4} + πn, x = \frac{3 π}{2} + 2 πn

Degrees

x = 13 5^{\circ} + 18 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

(cot (x) + 1) (sin (x) + 1) = 0

Solving each part separately

cot (x) + 1 = 0 or sin (x) + 1 = 0

cot (x) + 1 = 0 : x = \frac{3 π}{4} + πn

cot (x) + 1 = 0

Move

1

to the right side

cot (x) + 1 = 0

Subtract

1

from both sides

cot (x) + 1 - 1 = 0 - 1

Simplify

cot (x) = - 1

cot (x) = - 1

General solutions for

cot (x) = - 1

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

sin (x) + 1 = 0 : x = \frac{3 π}{2} + 2 πn

sin (x) + 1 = 0