What is the general solution for (cot(x)+1)(sin(x)+1)=0 ?

The general solution for (cot(x)+1)(sin(x)+1)=0 is x=(3pi)/4+pin,x=(3pi)/2+2pin

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(cot(x)+1)(sin(x)+1)=0

(cot (x) + 1) (sin (x) + 1) = 0

x = \frac{3 π}{4} + πn, x = \frac{3 π}{2} + 2 πn

Solution steps

(cot (x) + 1) (sin (x) + 1) = 0

Solving each part separately

cot (x) + 1 = 0 or sin (x) + 1 = 0

cot (x) + 1 = 0 : x = \frac{3 π}{4} + πn

sin (x) + 1 = 0 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{4} + πn, x = \frac{3 π}{2} + 2 πn

cos^{2} (x) - 2 sin (x) = 0

sin (x) cos (2 x) + cos (x) sin (2 x) = \frac{1}{2}

sin (3 x) - 3 sin (x) = 0

sin (x) = \frac{2.1}{4}

2 sec^{2} (x) + tan^{2} (x) = 3

What is the general solution for (cot(x)+1)(sin(x)+1)=0 ?
The general solution for (cot(x)+1)(sin(x)+1)=0 is x=(3pi)/4+pin,x=(3pi)/2+2pin