What is the general solution for cos(b)+4=3cos(b)+4 ?

The general solution for cos(b)+4=3cos(b)+4 is b= pi/2+2pin,b=(3pi)/2+2pin

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cos(b)+4=3cos(b)+4

cos (b) + 4 = 3 cos (b) + 4

b = \frac{π}{2} + 2 πn, b = \frac{3 π}{2} + 2 πn

Solution steps

cos (b) + 4 = 3 cos (b) + 4

Solve by substitution

cos (b) = 0

cos (b) = 0 : b = \frac{π}{2} + 2 πn, b = \frac{3 π}{2} + 2 πn

Combine all the solutions

b = \frac{π}{2} + 2 πn, b = \frac{3 π}{2} + 2 πn

- 3 cos (2 θ) - 15 sin (θ) + 8 = - 8 sin (θ) + 3

cos (z) = 4

sin (x) = 8

tan (y) = 0

sin (θ) = \frac{6}{10}

What is the general solution for cos(b)+4=3cos(b)+4 ?
The general solution for cos(b)+4=3cos(b)+4 is b= pi/2+2pin,b=(3pi)/2+2pin