What is the general solution for 2arccos(x)=pi ?

The general solution for 2arccos(x)=pi is x=0

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2arccos(x)=pi

2 arccos (x) = π

x = 0

Solution steps

2 arccos (x) = π

Divide both sides by

2

arccos (x) = \frac{π}{2}

Apply trig inverse properties

x = 0

- 2 cos (θ) + 1 = 5 cos (θ) + 0

2 sin^{2} (θ) - sin (θ) = 0, 0 \leq θ < 2 π

cos (x^{2}) = \frac{1}{2}

sec^{2} (x) - 7 sec (x) = 0

e^{\frac{π}{2}} - e^{a r c t a n (1 + x^{2})} = 0

What is the general solution for 2arccos(x)=pi ?
The general solution for 2arccos(x)=pi is x=0