What is the general solution for 6arccos(5x)=5pi ?

The general solution for 6arccos(5x)=5pi is x=-(sqrt(3))/(10)

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6arccos(5x)=5pi

6 arccos (5 x) = 5 π

x = - \frac{3}{10}

Solution steps

6 arccos (5 x) = 5 π

Divide both sides by

6

arccos (5 x) = \frac{5 π}{6}

Apply trig inverse properties

5 x = - \frac{3}{2}

Solve

5 x = - \frac{3}{2} : x = - \frac{3}{10}

x = - \frac{3}{10}

sin (x) + sin (x) cot (x) = 0

arctan (θ) = 1

cos (2 θ) = - \frac{1}{2}, 0 \leq θ \leq 2 π

sin (2 x) = \frac{2}{5}

sin (2 x) + cos (x) = 0, 0 \leq x \leq 2 π

What is the general solution for 6arccos(5x)=5pi ?
The general solution for 6arccos(5x)=5pi is x=-(sqrt(3))/(10)