What is the general solution for 2cos(x)+2=sin^2(x) ?

The general solution for 2cos(x)+2=sin^2(x) is x=pi+2pin

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2cos(x)+2=sin^2(x)

2 cos (x) + 2 = sin^{2} (x)

x = π + 2 πn

Solution steps

2 cos (x) + 2 = sin^{2} (x)

Subtract

sin^{2} (x)

from both sides

2 cos (x) + 2 - sin^{2} (x) = 0

Rewrite using trig identities

1 + cos^{2} (x) + 2 cos (x) = 0

Solve by substitution

cos (x) = - 1

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

3 cot (\frac{1}{3} x) = 1

sin (x) = tan (\frac{x}{2})

2 sin^{2} (x) - 17 sin (x) + 8 = 0

4 cos^{2} (t) sin (t) - 2 cos (t) sin (t) = 0

3 (1 - sin (θ)) = 2 cos^{2} (θ)

What is the general solution for 2cos(x)+2=sin^2(x) ?
The general solution for 2cos(x)+2=sin^2(x) is x=pi+2pin