What is the general solution for 2+sin(x)=5sin(x) ?

The general solution for 2+sin(x)=5sin(x) is x= pi/6+2pin,x=(5pi)/6+2pin

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Popular >

2+sin(x)=5sin(x)

Solution

2 + sin (x) = 5 sin (x)

Solution

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Degrees

x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n

Solution steps

2 + sin (x) = 5 sin (x)

Solve by substitution

2 + sin (x) = 5 sin (x)

Let:

sin (x) = u

2 + u = 5 u

2 + u = 5 u : u = \frac{1}{2}

2 + u = 5 u

Move

2

to the right side

2 + u = 5 u

Subtract

2

from both sides

2 + u - 2 = 5 u - 2

Simplify

u = 5 u - 2

u = 5 u - 2

Move

5 u

to the left side

u = 5 u - 2

Subtract

5 u

from both sides

u - 5 u = 5 u - 2 - 5 u

Simplify

- 4 u = - 2

- 4 u = - 2

Divide both sides by

- 4

- 4 u = - 2

Divide both sides by

- 4

\frac{- 4 u}{- 4} = \frac{- 2}{- 4}

Simplify

\frac{- 4 u}{- 4} = \frac{- 2}{- 4}

Simplify

\frac{- 4 u}{- 4} : u

\frac{- 4 u}{- 4}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{4 u}{4}

Divide the numbers:

\frac{4}{4} = 1

= u

Simplify

\frac{- 2}{- 4} : \frac{1}{2}

\frac{- 2}{- 4}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2}{4}

Cancel the common factor:

2

= \frac{1}{2}

u = \frac{1}{2}

u = \frac{1}{2}

u = \frac{1}{2}

Substitute back

u = sin (x)

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Popular Examples

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2 cos (θ) + 5 = 0

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sin (x) cos (x) = cos (x)

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2 cos (2 θ) + 1 = 0, 0 \leq θ \leq 2 π

cot(x)sin(x)+cot(x)=0

cot (x) sin (x) + cot (x) = 0

4cos(2θ)=4sin(2θ)

4 cos (2 θ) = 4 sin (2 θ)

Frequently Asked Questions (FAQ)

What is the general solution for 2+sin(x)=5sin(x) ?
The general solution for 2+sin(x)=5sin(x) is x= pi/6+2pin,x=(5pi)/6+2pin