What is the general solution for 2=sec(x)+sec^2(x) ?

The general solution for 2=sec(x)+sec^2(x) is x=2pin,x=(2pi)/3+2pin,x=(4pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2=sec(x)+sec^2(x)

2 = sec (x) + sec^{2} (x)

x = 2 πn, x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

2 = sec (x) + sec^{2} (x)

Switch sides

sec (x) + sec^{2} (x) = 2

Solve by substitution

sec (x) = 1, sec (x) = - 2

sec (x) = 1 : x = 2 πn

sec (x) = - 2 : x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Combine all the solutions

x = 2 πn, x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

4 cos (θ) - 5 = 0

cos (u) = - \frac{24}{25}

4 sin (y) = \frac{1}{cos ( y )}

2 cos (x) sin (x) = sin (x)

2 cos (θ) = 2 sin (θ)

What is the general solution for 2=sec(x)+sec^2(x) ?
The general solution for 2=sec(x)+sec^2(x) is x=2pin,x=(2pi)/3+2pin,x=(4pi)/3+2pin