What is the general solution for 3sin(b)+3=5sin(b)+2 ?

The general solution for 3sin(b)+3=5sin(b)+2 is b= pi/6+2pin,b=(5pi)/6+2pin

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3sin(b)+3=5sin(b)+2

3 sin (b) + 3 = 5 sin (b) + 2

b = \frac{π}{6} + 2 πn, b = \frac{5 π}{6} + 2 πn

Solution steps

3 sin (b) + 3 = 5 sin (b) + 2

Solve by substitution

sin (b) = \frac{1}{2}

sin (b) = \frac{1}{2} : b = \frac{π}{6} + 2 πn, b = \frac{5 π}{6} + 2 πn

Combine all the solutions

b = \frac{π}{6} + 2 πn, b = \frac{5 π}{6} + 2 πn

8 tan^{2} (θ) + 10 tan (θ) + 10 = 7

3 sec (x) - 23 = 0

2 cos (x) - 3 = - 5

sin (3 θ) - sin (θ) = cos (2 θ)

2 sin (x) + (2 - 3) = 3 csc (x)

What is the general solution for 3sin(b)+3=5sin(b)+2 ?
The general solution for 3sin(b)+3=5sin(b)+2 is b= pi/6+2pin,b=(5pi)/6+2pin