What is the general solution for solvefor x,2sin(x)+1=0 ?

The general solution for solvefor x,2sin(x)+1=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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solvefor x,2sin(x)+1=0

solve for

x, 2 sin (x) + 1 = 0

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

2 sin (x) + 1 = 0

Move

1

to the right side

2 sin (x) = - 1

Divide both sides by

2

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

8 tan (3 x) = 8

1 = sin (θ) - cos (θ)

2 - cos (θ) = 2 sin^{2} (θ)

tan (2 x - \frac{π}{6}) = 1, 0 \leq x \leq 2 π

cos (kπ) = - 1

What is the general solution for solvefor x,2sin(x)+1=0 ?
The general solution for solvefor x,2sin(x)+1=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin