What is the general solution for -2cos(2x)=0 ?

The general solution for -2cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-2cos(2x)=0

- 2 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

- 2 cos (2 x) = 0

Divide both sides by

- 2

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

sin (7 x) - 1 = 0

cos (x) (2 sin (x) - 1) = 0

tan (\frac{1}{2} x) = 3 cos (\frac{1}{2} x)

cos (2 θ) = - \frac{1}{2}, 0 \leq x \leq 2 π

cos (x) = - \frac{5}{13}

What is the general solution for -2cos(2x)=0 ?
The general solution for -2cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin