What is the general solution for tan^2(x)+2tan(x)=0 ?

The general solution for tan^2(x)+2tan(x)=0 is x=pin,x=-1.10714…+pin

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tan^2(x)+2tan(x)=0

Solution

tan^{2} (x) + 2 tan (x) = 0

Solution

x = πn, x = - 1.10714 \dots + πn

Degrees

x = 0^{\circ} + 18 0^{\circ} n, x = - 63.43494 \dots^{\circ} + 18 0^{\circ} n

Solution steps

tan^{2} (x) + 2 tan (x) = 0

Solve by substitution

tan^{2} (x) + 2 tan (x) = 0

Let:

tan (x) = u

u^{2} + 2 u = 0

u^{2} + 2 u = 0 : u = 0, u = - 2

u^{2} + 2 u = 0

Solve with the quadratic formula

u^{2} + 2 u = 0

Quadratic Equation Formula:

For

a = 1, b = 2, c = 0

u_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

u_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

2^{2} - 4 \cdot 1 \cdot 0

Apply rule

0 \cdot a = 0

= 2^{2} - 0

2^{2} - 0 = 2^{2}

= 2^{2}

Apply radical rule:

assuming

a \geq 0

= 2

u_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 2 + 2}{2 \cdot 1}, u_{2} = \frac{- 2 - 2}{2 \cdot 1}

u = \frac{- 2 + 2}{2 \cdot 1} : 0

\frac{- 2 + 2}{2 \cdot 1}

Add/Subtract the numbers:

- 2 + 2 = 0

= \frac{0}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{0}{2}

Apply rule

\frac{0}{a} = 0, a \neq = 0

= 0

u = \frac{- 2 - 2}{2 \cdot 1} : - 2

\frac{- 2 - 2}{2 \cdot 1}

Subtract the numbers:

- 2 - 2 = - 4

= \frac{- 4}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{- 4}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= - 2

The solutions to the quadratic equation are:

u = 0, u = - 2

Substitute back

u = tan (x)

tan (x) = 0, tan (x) = - 2

tan (x) = 0, tan (x) = - 2

tan (x) = 0 : x = πn

tan (x) = 0

General solutions for

tan (x) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = 0 + πn

x = 0 + πn

Solve

x = 0 + πn : x = πn

x = 0 + πn

0 + πn = πn

x = πn

x = πn

tan (x) = - 2 : x = arctan (- 2) + πn

tan (x) = - 2

Apply trig inverse properties

tan (x) = - 2

General solutions for

tan (x) = - 2

tan (x) = - a \Rightarrow x = arctan (- a) + πn

x = arctan (- 2) + πn

x = arctan (- 2) + πn

Combine all the solutions

x = πn, x = arctan (- 2) + πn

Show solutions in decimal form

x = πn, x = - 1.10714 \dots + πn

Popular Examples

sin(2x)+3sin(x)=0

sin (2 x) + 3 sin (x) = 0

(cos^3(x))/(sin(x))=cot(x)

\frac{cos ^{3} ( x )}{sin ( x )} = cot (x)

tan(2x)= 3/4

tan (2 x) = \frac{3}{4}

sin(x)=1+cos(x)

sin (x) = 1 + cos (x)

sqrt(2)sin(x)=sqrt(1+(cos(2x))/(sin(x)))

2 sin (x) = 1 + \frac{cos ( 2 x )}{sin ( x )}

Frequently Asked Questions (FAQ)

What is the general solution for tan^2(x)+2tan(x)=0 ?
The general solution for tan^2(x)+2tan(x)=0 is x=pin,x=-1.10714…+pin