What is the general solution for 1+cos(2x)=0 ?

The general solution for 1+cos(2x)=0 is x= pi/2+pin

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1+cos(2x)=0

1 + cos (2 x) = 0

x = \frac{π}{2} + πn

Solution steps

1 + cos (2 x) = 0

Move

1

to the right side

cos (2 x) = - 1

General solutions for

cos (2 x) = - 1

2 x = π + 2 πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = \frac{π}{2} + πn

cos^{2} (x) - sin^{2} (x) = \frac{3}{2}

2 sin^{2} (x) + 1 = 4 sin (x)

\frac{1}{4} = cos (x)

cos (2 x) + 3 cos (x) = - 2

4 tan^{2} (θ) + 16 tan (θ) = 7 tan (θ) - 2

What is the general solution for 1+cos(2x)=0 ?
The general solution for 1+cos(2x)=0 is x= pi/2+pin